In the hydrocarbon $$ \underset{8}{\mathrm{CH}_3}-\mathrm{CH}=\underset{4}{\mathrm{CH}}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}_1 $$ The state of hybridization of carbons 1,3 and 5 are in the following sequence

• A

  $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}$
• B

  $\mathrm{sp}^2, \mathrm{sp}, \mathrm{sp}^3$
• Correct answer
  C

  $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}_3^2$
• D

  $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$

Hence, the correct answer is option: 'C'.