Q138 / 200 · MHT CET - Medical 2026 (21 April Shift 1) · Chemistry
In the given reaction, the product "Z" is -
$\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\large{\text{Cu / 573 K . oxidation}}} \text{Z}$
$\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\large{\text{Cu / 573 K . oxidation}}} \text{Z}$
- A$\text{CH}_3\text{-CHO}$
- Correct answerB$\text{CH}_3\text{-CO-CH}_3$
- C$\text{CH}_3\text{-CH=CH}_2$
- D$\text{CH}_3\text{-CH}_2\text{-COOH}$
Solution
The given reactant is $\text{CH}_3\text{-CH(OH)-CH}_3$, which is propan-2-ol, a secondary alcohol.
When vapours of a secondary alcohol are passed over heated copper at $573 \text{ K}$, it undergoes dehydrogenation to form a ketone.
$\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\text{Cu / 573 K}} \text{CH}_3\text{-CO-CH}_3 + \text{H}_2$
Thus, the product Z is propanone (acetone), $\text{CH}_3\text{-CO-CH}_3$.
Answer: $\text{CH}_3\text{-CO-CH}_3$
When vapours of a secondary alcohol are passed over heated copper at $573 \text{ K}$, it undergoes dehydrogenation to form a ketone.
$\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\text{Cu / 573 K}} \text{CH}_3\text{-CO-CH}_3 + \text{H}_2$
Thus, the product Z is propanone (acetone), $\text{CH}_3\text{-CO-CH}_3$.
Answer: $\text{CH}_3\text{-CO-CH}_3$
Hence, the correct answer is option: 'B'.