In the given circuit, the binary inputs at $A$ and $B$ are both 1 in one case and both 0 in the next case. The respective outputs at $Y$ in these two cases will be

• A

  1,1
• Correct answer
  B

  0,0
• C

  0,1
• D

  1,0

Solution

The output of logic gate circuit for $$ \begin{array}{l} Y=\frac{}{A \cdot B+\bar{A} \bar{B}} \\ A=1 \end{array} $$ $$ B=1 \Rightarrow Y=0 $$ and for $\quad A=0, B=0$ $\Rightarrow \quad Y=0$

Hence, the correct answer is option: 'B'.