In the following sequence of reactions, ${\mathrm{C}}_3{\mathrm{H}}_6\stackrel{{\mathrm{H}}^{+}/{\mathrm{H}}_2\mathrm{O}}{⟶}\mathrm{A}\frac{\mathrm{KIO}}{\mathrm{dilKOH}}\mathrm{B}+\mathrm{C}$.  The compounds $\mathrm{B}$ and $\mathrm{C}$ respectively are :

• A

  ${\mathrm{CI}}_3\mathrm{COOK}, {\mathrm{CH}}_3\mathrm{I}$
• B

  ${\mathrm{CH}}_3\mathrm{I}, \mathrm{HCOOK}$
• C

  ${\mathrm{CI}}_3\mathrm{COOK}, \mathrm{HCOOH}$
• Correct answer
  D

  ${\mathrm{CHI}}_3, {\mathrm{CH}}_3\mathrm{COOK}$

Hence, the correct answer is option: 'D'.