In the following reaction, $$ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Br} \frac{\text { (i) } \mathrm{Mg}, \text { Ether }}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}} \mathrm{X} $$ the product ' $\mathrm{X}^{\prime}$ is

• A

  $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{C}_{6} \mathrm{H}_{5}$
• B

  $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$
• Correct answer
  C

  $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}$,
• D

  $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C}_{6} \mathrm{H}_{5}$

Hence, the correct answer is option: 'C'.