Q16 / 110 · VITEEE 2023 · Chemistry
Acetylene, on reacting with formaldehyde under high pressure, gives
- Apropanol
- Bpropyl alcohol
- Callyl aldehyde
- Correct answerDbutyndiol.
Solution
\(\underset{\text { acetylene }}{\mathrm{HC} \equiv \mathrm{CH}}+\underset{\text { formaldehyde }}{\mathrm{HCHO}} \stackrel{\text { High pressure }}{\longrightarrow} \mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}_2 \mathrm{OH}\)
\(\mathrm{HC} \equiv \mathrm{C}-\mathrm{CH}_2 \mathrm{OH}+\mathrm{H}-\stackrel{\huge \mathrm{H} \atop |}{\mathrm{C}}=\mathrm{O} \longrightarrow \underset{\text { But-2-yn, } 4 \text { diol }}{\mathrm{HOCH}_2 \equiv \mathrm{CCH}_2 \mathrm{OH}}\)
Therefore, acetylene with formaldehyde under high pressure forms by butyndiol.
Hence, the correct answer is option: 'D'.