In the following conversion, Identify ' $A$ ' from the following option

• A

  $\mathrm{NaBD}_4$
• B

  $\mathrm{LiAlD}_4$
• Correct answer
  C

  Mg, dry ether/ $\mathrm{D}_2 \mathrm{O}$
• D

  $\mathrm{BH}_3, \mathrm{D}_2 \mathrm{O}$

Solution

$\therefore$ ' $A$ ' is Mg, dry ether and $D_2 \mathrm{O}$.

Hence, the correct answer is option: 'C'.