Q159 / 160 · AP EAMCET 2015 · Physics
In the following circuit, the output $Y$ becomes zero for the input combinations.


- A$A=1, B=0, C=0$
- B$A=0, B=1, C=1$
- C$A=0, B=0, C=0$
- Correct answerD$A=1, B=1, C=0$
Solution
The output of the circuit is $Y=\bar{A}+\bar{B}+C$

$Y=\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\overline{\mathrm{C}}}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{C}$ If the output is zero, i.e. $Y=0$ then $A=1$ $B=1$ and $C=0$

$Y=\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\overline{\mathrm{C}}}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{C}$ If the output is zero, i.e. $Y=0$ then $A=1$ $B=1$ and $C=0$
Hence, the correct answer is option: 'D'.