Q39 / 54 · JEE Advanced 2022 (Paper 1) · Physics

In the following circuit $C_{1} = 12 μF, C_{2} = C_{3} = 4 μF$ and $C_{4} = C_{5} = 2 μF$ . The charge stored in $C_{3}$ is $μC .$

Correct answer: 8

Solution

From circuit given,
Capacitors $C_{2}, C_{3}, C_{4}$ and $C_{5}$ are in parallel connection with constant potential difference as $2 V$ .
Now, charge stored in $C_{3}$ is $Q_{3} = 2 \times 4 μC$ $= 8 μC$ .

Hence, the correct answer is 8.

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In the following circuit C1=12 μF,C2=C3=4 μF and C4=C5=2 μF. The charge stored in C3 is μC.

Solution

More Capacitance Questions

In the following circuit $C_{1} = 12 μF, C_{2} = C_{3} = 4 μF$ and $C_{4} = C_{5} = 2 μF$ . The charge stored in $C_{3}$ is $μC .$