Q80 / 90 · JEE Main 2024 (04 Apr Shift 2) · Physics

In simple harmonic motion, the total mechanical energy of given system is $E$. If mass of oscillating particle $P$ is doubled then the new energy of the system for same amplitude is: Figure

  • Correct answer
    A
    $E$
  • B
    $E / \sqrt{2}$
  • C
    $2 E$
  • D
    $E \sqrt{2}$

Solution

$\text {T.E. }=\frac{1}{2} \mathrm{kA}^2$ since A is same T.E. will be same.

Hence, the correct answer is option: 'A'.

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