In series LCR resonant circuit, $R=800 \Omega, C=2 \mu F$ and voltage across resistance is 200 V . The angular frequency is $250 \mathrm{rad} / \mathrm{s}$. At resonance, the voltage across the inductance is

Given: Series LCR circuit with $R = 800 \Omega$, $C = 2 \times 10^{-6}$ F, $V_R = 200$ V at angular frequency $\omega = 250$ rad/s.

At resonance, impedance becomes purely resistive, so the current is $I = \frac{V_R}{R} = \frac{200}{800} = 0.25$ A.

The capacitive reactance is $X_C = \frac{1}{\omega C} = \frac{1}{250 \cdot 2 \times 10^{-6}} = \frac{1}{5 \times 10^{-4}} = 2000 \Omega$.

Since $X_L = X_C$ at resonance, the inductive reactance is also $2000 \Omega$.

The voltage across the inductance is therefore $V_L = I \cdot X_L = 0.25 \times 2000 = 500$ V.

The voltage across the inductance at resonance is $500$ V.