Q105 / 150 · MHT CET 2025 (21 Apr Shift 1) · Physics

A physical quantity $A$ can be determined by measuring parameters $B$, $C, D$ and $E$ using the relation $A=\frac{B^\alpha C^\beta}{D^\gamma E^\delta}$. If the maximum errors in the measurement are b %, c %, d % and e % then maximum error in the value of $A$ is

  • A
    $(\alpha \mathrm{b}+\beta \mathrm{c}-\gamma \mathrm{d}-\delta \mathrm{e}) \%$
  • B
    $(b+c-d-e) \%$
  • Correct answer
    C
    $(\alpha \mathrm{b}+\beta \mathrm{c}+\gamma \mathrm{d}+\delta \mathrm{e}) \%$
  • D
    $(b+c+d+e) \%$

Solution

The maximum percentage error in quantity $A = \frac{B^{\alpha} C^{\beta}}{D^{\gamma} E^{\delta}}$ is derived using error propagation for multiplicative relationships.

Rewriting the expression as $A = B^{\alpha} C^{\beta} D^{-\gamma} E^{-\delta}$, the fractional error becomes:

$\frac{\Delta A}{A} = |\alpha| \frac{\Delta B}{B} + |\beta| \frac{\Delta C}{C} + |\gamma| \frac{\Delta D}{D} + |\delta| \frac{\Delta E}{E}$

Multiplying by 100 to convert to percentage errors:

$\left(\frac{\Delta A}{A} \times 100\right)\% = \alpha b\% + \beta c\% + \gamma d\% + \delta e\%$

The maximum percentage error in $A$ is therefore $(\alpha b + \beta c + \gamma d + \delta e)\%$, corresponding to option C.

Hence, the correct answer is option: 'C'.

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