In optical communication systems operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz…

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In optical communication systems operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is 10^n. The value of n is

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Correct answer: 6. The frequency of optical communication is given by, v=c/(λ) or v=(3×10^8)/(1200×10^(-9)) v=25×10^13 Hz But only 2% of the source frequency is available for TV transmission. v^(′)=2.5×10^14 ×2% v^(′)=2.5×10^14 ×2/100 v^(′)=5×10^12 Hz ∴ Number of channels=(v^(′))/bandwidth No of channels=(5×10^12)/(5×10^6)=10^6=1 million

In optical communication systems operating at $1200 nm$ , only $2 %$ of the source frequency is available for TV transmission having a bandwidth of $5 MHz$ . The number of TV channels that can be transmitted is $10^{n}$ . The value of $n$ is

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In optical communication systems operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is 10n. The value of n is

Solution

More Communication System Questions

In optical communication systems operating at $1200 nm$ , only $2 %$ of the source frequency is available for TV transmission having a bandwidth of $5 MHz$ . The number of TV channels that can be transmitted is $10^{n}$ . The value of $n$ is