In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz…

Question

In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is

MARKS Content Team · Accepted Answer

Correct answer: (D) 1 million. The frequency optical communication v=c/(λ) or v=(3×10^8)/(1200×10^(-9)) v=25×10^13 Hz But only 2% of the source frequency is available for TV transmission v^(′)=2.5×10^14 ×2% Or v^(′)=2.5×10^14 ×2/100 Or v^(′)=5×10^12 Hz ∴ Number of channels=(v^(′))/bandwidth Or No of channels=(5×10^12)/(5×10^6)=10^6=1 million

In optical communication system operating at $1200 nm$ , only $2 %$ of the source frequency is available for TV transmission having a bandwidth of $5 MHz$ . The number of TV channels that can be transmitted is

Solution

More Communication System Questions