Q51 / 200 · NEET 2003 · Chemistry

In Haber process 3 litres of dihydrgen and 30 litres of dinitrogen were taken for reaction which yielded only $50 \%$ of the expected product. What will be the composition of gaseous mixture under the above said condition in the end?

  • A
    20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
  • Correct answer
    B
    10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
  • C
    20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
  • D
    20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen

Solution

$\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3$ $1 \mathrm{~mol} \quad 3 \mathrm{~mol} 2 \mathrm{~mol}$ 2 vol $3 \mathrm{~mol} 2 \mathrm{vol}$ $(\operatorname{mol} \%=\operatorname{vol} \%)$ $$ \begin{aligned} & \begin{array}{l} 10 \mathrm{vol} \quad 30 \mathrm{vol} \quad 20 \mathrm{vol} \\ \text { (expected = product) } \end{array} \\ & (30-x)(30-x) 2 x \\ & \text { Given that } 2 x=20 \times \frac{50}{100}=10 \\ & \therefore \quad x=5 \end{aligned} $$ Composition of gaseous mixture $$ \begin{aligned} \mathrm{N}_2 & =(30-x)=25 \text { litre } \\ \mathrm{H}_2 & =(30-3 x)=15 \text { litre } \\ \mathrm{NH}_3 & =2 x=10 \text { litre } \end{aligned} $$

Hence, the correct answer is option: 'B'.

Relevant Questions