Q28 / 160 · WBJEE 2011 · Chemistry

In aqueous solution glucose remains as

  • A
    Only in open chain form
  • B
    Only in pyranoze form
  • C
    Only in furanose forms
  • Correct answer
    D
    In all three forms in equilibrium

Solution

Hints: \(\begin{aligned} & \beta-\mathrm{D}-\text { glucose } \rightleftharpoons \mathrm{D}-\text { glucose } \rightleftharpoons \alpha-\mathrm{D}-\text { glucose } \\ & (\approx 64 \%) \quad\qquad(\text {open chain } \approx 0.02 \%) \qquad~~(\approx 34 \%)\end{aligned}\)

Hence, the correct answer is option: 'D'.

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