Q118 / 150 · MHT CET 2025 (19 Apr Shift 2) · Physics
In an organ pipe closed at one end, the sum of the frequencies of first three overtones is 3930 Hz . The frequency of the fundamental mode of organ pipe is
- A256 Hz
- Correct answerB262 Hz
- C320 Hz
- D384 Hz
Solution
For an organ pipe closed at one end, the harmonic frequencies are odd multiples of the fundamental frequency $f_1$. The first three overtones correspond to the third, fifth, and seventh harmonics, with frequencies $3f_1$, $5f_1$, and $7f_1$, respectively.
The sum of these overtone frequencies is given as 3930 Hz:
$3f_1 + 5f_1 + 7f_1 = 3930$
which simplifies to
$15f_1 = 3930$
Solving for $f_1$:
$f_1 = \frac{3930}{15} = 262$ Hz
The fundamental frequency is 262 Hz, corresponding to option B.
Hence, the correct answer is option: 'B'.