Q79 / 200 · NEET 2012 (Screening) · Chemistry

In a zero order reaction for every $10^{\circ}$ rise of temperature, the rate is doubled. If the temperature is increased from $10^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, the rate of the reaction will become

  • A
    256 times
  • Correct answer
    B
    512 times
  • C
    64 times
  • D
    128 times

Solution

For $10^{\circ}$ rise in temperature, $n=1$ so rate $=2^n=2^1=2$ When temperature is increased from $10^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$, change in temperature $=100-10=90^{\circ} \mathrm{C}$, i.e., $n=9$ So, rate $=2^9=512$ times Alternate method With every $10^{\circ}$ rise in temperature, rate becomes double, so $\frac{r^{\prime}}{r}=2^{\left(\frac{100-10}{10}\right)}=2^9=512$ times.

Hence, the correct answer is option: 'B'.

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