Q79 / 200 · NEET 2023 (Manipur) · Chemistry
For a reaction $3 \mathrm{~A} \rightarrow 2 \mathrm{~B}$
The average rate of appearance of $B$ is given by $\frac{\Delta[B]}{\Delta t}$. The correct relation between the average rate of appearance of $B$ with the average rate of disappearance of $A$ is given in option
- Correct answerA$\frac{-2 \Delta[\mathrm{A}]}{3 \Delta \mathrm{t}}$
- B$\frac{\Delta[\mathrm{A}]}{\Delta \mathrm{t}}$
- C$\frac{-\Delta[\mathrm{A}]}{\Delta \mathrm{t}}$
- D$\frac{-3 \Delta[\mathrm{A}]}{2 \Delta \mathrm{t}}$
Solution
For reaction, $3 \mathrm{~A} \longrightarrow 2 \mathrm{~B}$
Average rate of reaction $=-\frac{1}{3} \frac{\Delta[\mathrm{A}]}{\Delta \mathrm{t}}=\frac{1}{2} \frac{\Delta[\mathrm{B}]}{\Delta \mathrm{t}}$
So $\frac{\Delta[\mathrm{B}]}{\Delta \mathrm{t}}=-\frac{2}{3} \frac{\Delta[\mathrm{A}]}{\Delta \mathrm{t}}$
Hence, the correct answer is option: 'A'.