Q134 / 160 · TS EAMCET 2023 (13 May Shift 2) · Physics

In a well pressure at a point $10 \mathrm{~m}$ below the surface of water is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$

  • A
    $2 \times 10^4 \mathrm{Nm}^{-2}$
  • B
    $10^5 \mathrm{Nm}^{-2}$
  • C
    $10^4 \mathrm{Nm}^{-2}$
  • Correct answer
    D
    $2 \times 10^5 \mathrm{Nm}^{-2}$

Solution

The total pressure at the given depth. $$ \begin{aligned} & =P_0+\Delta p \\ & =P_0+\rho g h \\ & =1.01 \times 10^5+1000 \times 10 \times 10 \end{aligned} $$ $\begin{aligned} & =1.01 \times 10^5+10^5 \\ & =2.01 \times 10^5 \mathrm{Nm}^{-2} \\ & =2 \times 10^5 \mathrm{Nm}^{-2}\end{aligned}$

Hence, the correct answer is option: 'D'.

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