Q109 / 180 · AIIMS 2014 · Physics

In a uniform electric field a charge of $3 \mathrm{C}$ experiences a force of $3000 \mathrm{~N}$. The potential difference between two points $1 \mathrm{~cm}$ apart along the electric line of force will be

  • Correct answer
    A
    $10 \mathrm{~V}$
  • B
    $30 \mathrm{~V}$
  • C
    $300 \mathrm{~V}$
  • D
    $100 \mathrm{~V}$

Solution

As $E=\frac{F}{q}=\frac{3000 \mathrm{~N}}{3 \mathrm{C}}=1000 \mathrm{NC}^{-1}$. $d r=1 \mathrm{~cm}=10^{-2} \mathrm{~m}$ $d V=E(d r)=1000 \times 10^{-2}=10 \mathrm{~V}$

Hence, the correct answer is option: 'A'.

Relevant Questions