Q23 / 108 · NTA Abhyas (JEE Main) 2020 · Mathematics · Probability

In a test, an examinee either guesses or copies or knows the answer to a multiple choice question with four choices. The probability that he makes a guess is 13 and the probability that he copies the answer is 16. The probability that his answer is correct given that he copies it is 18. The probability that his answer is correct, given that he guesses it is 14. The probability that he knew the answer to the question given that he correctly answered, is

  • A
    2431
  • B
    1724
  • Correct answer
    C
    2429
  • D
    2931

Solution

Let E1,E2 and E3 are the events that the examinee guesses, copies and knows the answer and E is the event that he answers correctly.

Then, P E 1 = 1 3 ,   P E 2 = 1 6

and P E 3 = 1 - 1 3 + 1 6 = 1 2

∴     Required probability = P E 3 E

  = P E E 3 · P E 3 P E E 1 · P E 1 + P E E 2 · P E 2 + P E E 3 · P E 3

  = 1 × 1 2 1 4 × 1 3 + 1 8 × 1 6 + 1 × 1 2 = 2 4 2 9

Hence, the correct answer is option: 'C'.

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