If x=33^n,n is a positive integral value, then the probability that x will have 3 at its units place is

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MARKS Content Team · Accepted Answer

Correct answer: (B) 1/4. Given that, x=33^n Where, n is a positive integral value. Here, only four digits may be at the unit place ie, 1, 3, 7, 9. ∴ nS=4 Let E be the event of getting 4 at its units place. ∴ nE=1 ∴ P E = (n E)/(n S) = 1/4

If $x = 33^{n}, n$ is a positive integral value, then the probability that $x$ will have $3$ at its units place is

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More Probability Questions

If x=33n,n is a positive integral value, then the probability that x will have 3 at its units place is

Solution

More Probability Questions

If $x = 33^{n}, n$ is a positive integral value, then the probability that $x$ will have $3$ at its units place is