In a series LCR circuit, if the current leads the source voltage, then

• Correct answer
  A

  $X_{\mathrm{C}} \gt X_{\mathrm{L}}$
• B

  $X_{\mathrm{L}} \gt X_{\mathrm{C}}$
• C

  $X_L=X_C \neq 0$
• D

  $X_L=X_C=0$

Solution

The phase difference between the current and the voltage in the series LCR circuit is $\tan \phi=\frac{\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}}{\mathrm{R}}$
And from phasor diagram, if the current is leading the voltage, then the phase difference should be negative. so from eq. (i) $X_C \gt X_L$

Hence, the correct answer is option: 'A'.