Q153 / 160 · TS EAMCET 2024 (09 May Shift 1) · Physics

If the amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 270 nT , the amplitude of the electric field part of the wave is

  • A
    $90 \mathrm{NC}^{-1}$
  • Correct answer
    B
    $81 \mathrm{NC}^{-1}$
  • C
    $9 \mathrm{NC}^{-1}$
  • D
    $30 \mathrm{NC}^{-1}$

Solution

Speed of light in vacuum $C=\frac{E_0}{B_0} \Rightarrow$ Amplitude of the electric field $\mathrm{E}_{\mathrm{o}}=\mathrm{CB}_0=3 \times 10^8 \times 270 \times 10^{-9}$ $=81 \mathrm{NC}^{-1}$

Hence, the correct answer is option: 'B'.

Relevant Questions