Q137 / 150 · MHT CET 2026 (15 April Shift 2) · Physics
In a cyclic process, work done by the system is
- Azero.
- Correct answerBequal to the heat given to system.
- Cmore than the heat given to system.
- Dindependent of heat given to system.
Solution
According to the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W$.
For a cyclic process, the initial and final states of the system are the same, so the change in internal energy is zero ($\Delta U = 0$).
Substituting $\Delta U = 0$ into the first law equation gives $\Delta Q = \Delta W$.
Therefore, the work done by the system is equal to the net heat given to the system.
Answer: equal to the heat given to system.
For a cyclic process, the initial and final states of the system are the same, so the change in internal energy is zero ($\Delta U = 0$).
Substituting $\Delta U = 0$ into the first law equation gives $\Delta Q = \Delta W$.
Therefore, the work done by the system is equal to the net heat given to the system.
Answer: equal to the heat given to system.
Hence, the correct answer is option: 'B'.