Q36 / 122 · NTA Abhyas (JEE Main) 2020 · Physics · Rotational Motion

In a continuous printing process, paper roll is wrapped on a cylindrical core which is free to rotate about a fixed horizontal axis. The paper is drawn into the process at a constant speed v, as shown in the figure. If r is the radius of paper on the roll at any given time and b is the thickness of the paper, then the angular acceleration of the roll at this instant is
Figure

  • A
    v2b2π2r3
  • B

    zero because v is constant

  • Correct answer
    C
    v2b2πr3
  • D
    cannot be calculated from given information

Solution

In a continuous printing process suppose the total length of paper is l.

If r1 is the inner radius of roll then, πr2-πr12=l×b             ...(i)
And at this moment, v=rω     ...(ii)    
Figure

Differentiating equation (i) w.r.t. time,
⇒π×2rdrdt=dldt·b
⇒drdt=v.b2πr          ...(iii)

Differentiating equation (ii) w.r.t time
⇒dvdt=rdωdt+ωdrdt
⇒0=rα+ωdrdt           ∵drdtis-ve
⇒drdt=rαω
⇒α=ωrdrdt           ...(iv)

Using (iii) and (iv), vb.ω2πr2=v2b2πr3=α

Hence, the correct answer is option: 'C'.

More Rotational Motion Questions