Q28 / 125 · BITSAT 2016 · Chemistry
In a closed system, $\mathrm{A}(\mathrm{s}) \rightleftharpoons 2 \mathrm{~B}(\mathrm{~g})+3 \mathrm{C}(\mathrm{g})$, if partial
pressure of $\mathrm{C}$ is doubled, then partial pressure of $\mathrm{B}$ will be
- A$2 \sqrt{2}$ times the original value
- B$\frac{1}{2}$ times the original value
- C2 times the original value
- Correct answerD$\frac{1}{2 \sqrt{2}}$ times the original value
Solution
$\quad K_{p}=p_{B_{1}}^{2} \times p_{C_{1}}^{3}$
Again, $K_{p}=p_{B_{2}}^{2} \times\left(2 p_{C_{1}}\right)^{3}$
$\therefore \mathrm{p}_{\mathrm{B}_{1}}^{2} \times \mathrm{p}_{\mathrm{C}_{1}}^{3}=\mathrm{P}_{\mathrm{B}_{2}}^{2} \times 8 \mathrm{p}_{\mathrm{C}_{1}}^{3}$
$$
\therefore \frac{\mathrm{p}_{\mathrm{B}_{1}}^{2}}{8}=\mathrm{p}_{\mathrm{B}_{2}}^{2} \text { or, } \frac{\mathrm{p}_{\mathrm{B}_{1}}}{2 \sqrt{2}}=\mathrm{p}_{\mathrm{B}_{2}}
$$
Hence, the correct answer is option: 'D'.