Q114 / 160 · JIPMER 2013 · Physics

In 0.2 s, the current in a coil increases from 2.0 A to 3.0 A. If inductance of coil is 60 mH, then induced current in external resistance of $3 \Omega$ will be

  • A
    1 A
  • B
    0.5 A
  • C
    0.2 A
  • Correct answer
    D
    0.1 A

Solution

Induced emf $\begin{aligned}|e| & =L \frac{d i}{d t}=\left(60 \times 10^{-3}\right) \times \frac{(3.0-2.0)}{0.2} \\ & =\frac{60 \times 10^{-3} \times 1}{0.2}=0.3 \mathrm{~V}\end{aligned}$ Induced current, $\mathrm{t} i=\frac{e}{R}=\frac{0.3}{3}=0.1 \mathrm{~A}$

Hence, the correct answer is option: 'D'.

More Electromagnetic Induction Questions