Q121 / 160 · JIPMER 2010 · Physics
In 0.1 s , the current in a coil increases from 1 A to 1.5A. If inductance of coil is 60 mH , then induced current in external resistance of $3 \Omega$ will be
- A1A
- B0.5A
- C0.2A
- Correct answerD0.1A
Solution
Induced emf,
$\begin{aligned}
|e|=L \frac{d i}{d t} & =\left(60 \times 10^{-3}\right) \times \frac{(1.5-1)}{0.1} \\
& =\frac{60 \times 10^{-3} \times 0.5}{0.1}=0.3 \mathrm{~V}
\end{aligned}$
Induced current,
$i=\frac{e}{R}=\frac{0.3}{3}=0.1 \mathrm{~A}$
Hence, the correct answer is option: 'D'.