If $\cos \alpha+\cos \beta+\cos \gamma=0=\sin \alpha+\sin \beta+\sin \gamma$, then $\sin 2 \alpha+\sin 2 \beta+\sin 2 \gamma=$

• Correct answer
  A

  $\cos (\alpha+\beta)+\cos (\beta+\gamma)+\cos (\gamma+\alpha)$
• B

  $\cos ^2 \alpha+\cos ^2 \beta+\cos ^2 \gamma$
• C

  $\sin ^2 \alpha+\sin ^2 \beta+\sin ^2 \gamma$
• D

  $\cos (2 \alpha-\beta-\gamma)+\cos (2 \beta-\gamma-\alpha)+\cos (2 \gamma-\alpha-\beta)$

Hence, the correct answer is option: 'A'.