Q51 / 160 · TS EAMCET 2025 (03 May Shift 1) · Mathematics
If $\alpha$ is a root of the equation $x^2-x+1=0$ then $\left(\alpha+\frac{1}{\alpha}\right)^3+\left(\alpha^2+\frac{1}{\alpha^2}\right)^3+\left(\alpha^3+\frac{1}{\alpha^3}\right)^3+\left(\alpha^4+\frac{1}{\alpha^4}\right)^3+\ldots$ to 12 terms $=$
- A$-32$
- B$32$
- Correct answerC$0$
- D$16$
Hence, the correct answer is option: 'C'.