Q51 / 160 · TS EAMCET 2025 (03 May Shift 1) · Mathematics

If $\alpha$ is a root of the equation $x^2-x+1=0$ then $\left(\alpha+\frac{1}{\alpha}\right)^3+\left(\alpha^2+\frac{1}{\alpha^2}\right)^3+\left(\alpha^3+\frac{1}{\alpha^3}\right)^3+\left(\alpha^4+\frac{1}{\alpha^4}\right)^3+\ldots$ to 12 terms $=$

  • A
    $-32$
  • B
    $32$
  • Correct answer
    C
    $0$
  • D
    $16$

Hence, the correct answer is option: 'C'.

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