If $2 \operatorname{Tanh}^{-1} x=\operatorname{Sinh}^{-1}\left(\frac{4}{3}\right)$ then $\operatorname{Cosh}^{-1}\left(\frac{1}{x}\right)=$

• A

  $\log (\sqrt{2}+1)$
• B

  $\log (\sqrt{2}-1)$
• Correct answer
  C

  $\log (2+\sqrt{3})$
• D

  $\log (2-\sqrt{3})$

Hence, the correct answer is option: 'C'.