If $\mathrm{p}_1, \mathrm{p}_2, \mathrm{p}_3$ are the altitudes and $a=4, b=5, c=6$ are the sides of a triangle ABC, then $\frac{1}{\mathrm{p}_1{ }^2}+\frac{1}{\mathrm{p}_2{ }^2}+\frac{1}{\mathrm{p}_3{ }^2}=$

• A

  $\frac{77}{225}$
• Correct answer
  B

  $\frac{44}{225}$
• C

  $\frac{308}{225}$
• D

  $\frac{22}{75}$

Hence, the correct answer is option: 'B'.