If $f(t)=\int_0^t \tan ^{(2 n-1)} x d x, n \in N$, then $f(t+\pi)=$

• A

  $f(t) f(\pi)$
• B

  $\mathrm{f}(\mathrm{t})-\mathrm{f}(\pi)$
• Correct answer
  C

  $\mathrm{f}(\mathrm{t})+\mathrm{f}(\pi)$
• D

  $\frac{f(t)}{f(\pi)}$

Hence, the correct answer is option: 'C'.