If $k \in N$ then $\lim _{n \rightarrow \infty}\left[\frac{1}{n+1}+\frac{1}{n+2}+\frac{1}{n+3}+\ldots+\frac{1}{k n}\right]=$

• A

  $\log (k+1)$
• Correct answer
  B

  $\log \mathrm{k}$
• C

  $\log (k+5)$
• D

  $\log (\mathrm{k}+1)-\log 6$

Hence, the correct answer is option: 'B'.