If $A=\left[\begin{array}{ccc}1 & 2 & -2 \\ 2 & -1 & 2 \\ -1 & 1 & -2\end{array}\right]$, then $A+2 A^{-1}=$

• Correct answer
  A

  $\left[\begin{array}{ccc}1 & 4 & 0 \\ 4 & -5 & -4 \\ 0 & -2 & -7\end{array}\right]$
• B

  $\left[\begin{array}{ccc}0 & 2 & 2 \\ 2 & -4 & -6 \\ 2 & -3 & -5\end{array}\right]$
• C

  $\left[\begin{array}{ccc}0 & 2 & 1 \\ 2 & -4 & -3 \\ 2 & -6 & -5\end{array}\right]$
• D

  $\left[\begin{array}{ccc}1 & 4 & -1 \\ 4 & -5 & -1 \\ 1 & -5 & -7\end{array}\right]$

Hence, the correct answer is option: 'A'.