Q9 / 102 · NTA Abhyas (JEE Main) 2020 · Chemistry · Ionic Equilibrium

If the pK a of a weak acid HA is 4.80 and the pK b of a weak base BOH is 4.78. Then, the pH of an aqueous solution of the corresponding salt, BA will be

  • A
    8.23
  • B
    9.41
  • Correct answer
    C
    7.01
  • D
    5.91

Solution

BOH+HA→ B + + A − + H 2 O
pH= 1 2  pK w + 1 2   pK a − 1 2 pK b
=  1 2 14+4.80−4.78 =7.01

Hence, the correct answer is option: 'C'.

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