Q153 / 160 · TS EAMCET 2024 (11 May Shift 1) · Physics
If the peak value of the magnetic field of an electromagnetic wave is $30 \times 10^{-9} \mathrm{~T}$, then the peak value of the electric field is
- A$3 \mathrm{Vm}^{-1}$
- B$12 \mathrm{Vm}^{-1}$
- C$6 \mathrm{Vm}^{-1}$
- Correct answerD$9 \mathrm{Vm}^{-1}$
Solution
For EM wave,
$\mathbf{B}_{\mathrm{o}}=30 \times 10^{-9} \mathrm{~T}, \mathrm{C}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$
$\therefore$ Peak value of electric field is
$\mathrm{E}_{\mathrm{o}}=\mathrm{CB}_{\mathrm{o}}=3 \times 10^8 \times 30 \times 10^{-9}=9 \mathrm{Vm}^{-1}$
Hence, the correct answer is option: 'D'.