Q6 / 180 · KCET 2011 · Chemistry

If the energies of the two photons in the ratio of $3: 2$, their wavelength will be in the ratio of

  • Correct answer
    A
    $2: 3$
  • B
    $9: 4$
  • C
    $3: 2$
  • D
    $1: 2$

Solution

$E_{1}: E_{2}=\frac{h c}{\lambda_{1}}: \frac{h c}{\lambda_{2}}=\frac{1}{\lambda_{1}}: \frac{1}{\lambda_{2}}$ $3: 2=\frac{1}{\lambda_{1}}: \frac{1}{\lambda_{2}}=\frac{\lambda_{2}: \lambda_{1}}{\lambda_{1} \lambda_{2}}$ $\therefore \quad \lambda_{2}: \lambda_{1}=3: 2$ or $\lambda_{1}: \lambda_{2}=2: 3$

Hence, the correct answer is option: 'A'.

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