Q34 / 180 · KCET 2009 · Chemistry

A body of mass $x \mathrm{~kg}$ is moving with a velocity of $100 \mathrm{~ms}^{-1}$. Its de-Broglie wavelength is $6.62 \times 10^{-35} \mathrm{~m}$. Hence, $\mathrm{x}$ is $\left(\mathrm{h}=6.62 \times 10^{-34} \mathrm{Js}\right.$ )

  • Correct answer
    A
    $0.1 \mathrm{~kg}$
  • B
    $0.25 \mathrm{~kg}$
  • C
    $0.15 \mathrm{~kg}$
  • D
    $0.2 \mathrm{~kg}$

Solution

$\begin{aligned} \lambda &=\frac{\mathrm{h}}{\mathrm{mv}} \\ &=\frac{6.62 \times 10^{-34}}{6.62 \times 10^{-35} \times 100} \\ &=0.1 \mathrm{~kg} \end{aligned}$

Hence, the correct answer is option: 'A'.

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