Q114 / 180 · JIPMER 2018 · Physics

If the efficiency of an engine is $50 \%$ and its work output is 500 J , then find input.

  • Correct answer
    A
    $1000 J$
  • B
    $500 J$
  • C
    $100 J$
  • D
    $250 J$

Solution

$\because$ Efficiency, $\eta=\frac{\text { Workdone }}{\text { Heat input }} \times 100$ or $\frac{\eta}{100}=\frac{\text { Work done }}{\text { Heat input }}=\frac{500}{\text { Heat input }}$ Heat input $=\frac{500 \times 100}{50}=1000 \mathrm{~J}$

Hence, the correct answer is option: 'A'.

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