Q26 / 116 · NTA Abhyas (JEE Main) 2020 · Mathematics · Definite Integration

If the definite integral I=∫0πsin⁡xdx=∑ε=0naεsin⁡ε. (where,  ⋅ is the greatest integer function), then the value of an+nπ is equal to

Correct answer: 1

Solution

The given integral is
I=∫01sin⁡0dx+∫12sin⁡1dx+∫23sin⁡2dx+∫3πsin⁡3dx
⇒I=2-1sin⁡1+3-2sin⁡2+π-3sin⁡3
∴an=π-3
and n=3
⇒an+n=π or an+nπ=1

Hence, the correct answer is 1.

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