Q5 / 116 · NTA Abhyas (JEE Main) 2020 · Mathematics · Definite Integration

Consider I=∫01dx1+x5. Then, I satisfies

  • A
    I>1
  • B
    I=1
  • Correct answer
    C
    I<1
  • D
    I+1<0

Solution

As, x∈0,1
x5∈0,1
∴1+x5∈1,2
⇒1+x5>1
∴∫01dx1+x5<∫011dx
⇒I<1

Hence, the correct answer is option: 'C'.

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