Q21 / 150 · MHT CET 2020 (14 Oct Shift 2) · Chemistry

If the conductivity of $0.08 \mathrm{M}$ KCl solution is $2 \times 10^{-2} \Omega^{-1}$, what is the molar conductivity of the solution?

  • A
    350 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • Correct answer
    B
    250 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • C
    25.0 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • D
    0.25 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$

Solution

$\Lambda=\frac{1000 \mathrm{k}}{\mathrm{C}}=\frac{1000 \times 2 \times 10^{-2}}{0.08}=250 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$

Hence, the correct answer is option: 'B'.

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