If sin^(-1)⁡1/3+sin^(-1)⁡2/3=sin^(-1)⁡x, then the value of x is

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MARKS Content Team · Accepted Answer

Correct answer: (C) ((√5+4√2))/9. Given that, sin^(-1)⁡1/3+sin^(-1)⁡2/3=sin^1⁡x Taking sine on both sides ⇒⁡1/3√(1-49)+2/3√(1-19)=⁡x⇒⁡1^(3.53+23.83=)⁡x ⇒ ⁡(√5+4√2)/9=⁡x ∴ x=(√5+4√2)/9

If $\sin^{- 1} \frac{1}{3} + \sin^{- 1} \frac{2}{3} = \sin^{- 1} x$ , then the value of $x$ is

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More Inverse Trigonometric Functions Questions

If sin-1⁡13+sin-1⁡23=sin-1⁡x, then the value of x is

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More Inverse Trigonometric Functions Questions

If $\sin^{- 1} \frac{1}{3} + \sin^{- 1} \frac{2}{3} = \sin^{- 1} x$ , then the value of $x$ is