Q184 / 200 · Manipal (MET) 2011 · Physics

If $10 \%$ of the current passes through a moving coil galvanometer of resistance $99 \Omega$. Then the shunt resistance will be

A
$9.9 \Omega$
Correct answer
B
$11 \Omega$
C
$10 \Omega$
D
$9 \Omega$

Solution

Resistance of galvanometer $G=99 \Omega$ Resistance of shunt $S=\frac{i_g G}{i-i_g}$ $=\frac{10 \times 99}{100-10}=11 \Omega$

Hence, the correct answer is option: 'B'.

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