Q124 / 170 · Manipal (MET) 2016 · Physics

If $10 \%$ of the main current is to be passed through the moving coil galvanometer of resistance $99 \Omega$, then the required shunt resistance will be

  • A
    $9.9 \Omega$
  • B
    $10 \Omega$
  • Correct answer
    C
    $11 \Omega$
  • D
    $9 \Omega$

Solution

Here, $I_g=\frac{I}{10}, G=99 \Omega$ $\because$ The shunt, $\quad S=\frac{I_g}{I-I_g} \cdot G$ $\therefore \quad S=\frac{I / 10}{I-\frac{I}{10}} \times 99$ $\Rightarrow \quad S=11 \Omega$

Hence, the correct answer is option: 'C'.

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