Q38 / 97 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solutions

If latent heat of fusion of ice is 80 cals per $g$ at $0^{o} C$ , calculate molal depression constant for water.

A
18.63
B
186.3
Correct answer
C
1.863
D
0.1863

Solution

K_{f} = \frac{R T_{f}^{2}}{1000 \times l_{V}}

Here

R = 2 c a l s

,

T_{f} = 0 + 273 = 273, l_{f} = 80 c a l s

K_{f} = \frac{2 \times 273 \times 273}{1000 \times 80} = 1.863

Hence, the correct answer is option: 'C'.

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