Q12 / 155 · WBJEE 2019 · Chemistry

If electrolysis of aqueous CuSO $_{4}$ solution is carried out using Cu-electrodes, the reaction taking place at the anode is

  • A
    $\mathrm{H}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{H}$
  • B
    $\mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})$
  • C
    $\mathrm{SO}_{4}^{2-}(\mathrm{aq})-2 \mathrm{e}^{-} \rightarrow \mathrm{SO}_{4}$
  • Correct answer
    D
    $\mathrm{Cu}(\mathrm{s})-2 e^{-} \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})$

Solution

Electrolysis of copper sulphate solution using Cu-electrodes, Ions present : $\mathrm{Cu}^{2+}, \mathrm{H}^{+}, \mathrm{SO}_{4}^{2-}, \mathrm{OH}^{-}$ At cathode $\mathrm{Cu}^{2+}(a q)+2 e^{-} \rightarrow \mathrm{Cu}(s)$ At anode $\mathrm{Cu}(s)-2 e^{-} \rightarrow \mathrm{Cu}^{2+}(a q)$ So, the option (d) is correct answer.

Hence, the correct answer is option: 'D'.

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